This is a very nice mathematical one that can attract anybody and make them sit and work with their paper and pencil for even hours. Don’t scroll down to answer until you solve the problem or at least an hour has passed since you made an attempt.
You have a 3X3 table making a total of 9 small squares and you have to put
numbers, from 1 to 9, one number in each square. No number can be repeated and
no number left out. You have to put those numbers in each square so that if you
add up all the numbers in one row or one column or diagonally it should be 15.
Below is an example how to put it:
A C B
D F G
E H I
You have to put
numbers 1-9 (totally 9 numbers) in place of the letters A to I, in such a manner
that A+C+B=15, A+D+E=15, A+F+I=15, B+G+I=15
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Scroll down for the answer
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Answer:
4 3 8
9 5 1
2 7 6
You can take any 9 numbers, not necessarily 1 to 9 and if you arrange the numbers in the manner shown in the table that is the 4th, 5th and 6th letter making a diagonal and the rest of the numbers in their respective positions then you can make table of any 9 consecutive letters (10 to 18, the row or column summation being 13+14+15=42).
